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Apply the formula: $a^x=b$$\to \log_{a}\left(a^x\right)=\log_{a}\left(b\right)$, where $a=2$, $b=\left(\frac{1}{8}\right)^{\left(1-5x\right)}$ and $x=6x+7$
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$\log_{2}\left(2^{\left(6x+7\right)}\right)=\log_{2}\left(\left(\frac{1}{8}\right)^{\left(1-5x\right)}\right)$
Learn how to solve equations exponentielles problems step by step online. Solve the exponential equation 2^(6x+7)=(1/8)^(1-5x). Apply the formula: a^x=b\to \log_{a}\left(a^x\right)=\log_{a}\left(b\right), where a=2, b=\left(\frac{1}{8}\right)^{\left(1-5x\right)} and x=6x+7. Apply the formula: \log_{b}\left(b^a\right)=a, where a=6x+7 and b=2. Apply the formula: x+a=b\to x+a-a=b-a, where a=7, b=\log_{2}\left(\left(\frac{1}{8}\right)^{\left(1-5x\right)}\right), x+a=b=6x+7=\log_{2}\left(\left(\frac{1}{8}\right)^{\left(1-5x\right)}\right), x=6x and x+a=6x+7. Apply the formula: x+a+c=b+f\to x=b-a, where a=7, b=\log_{2}\left(\left(\frac{1}{8}\right)^{\left(1-5x\right)}\right), c=-7, f=-7 and x=6x.
