$\frac{d}{dx}\left(\mathrm{arccot}\left(\sqrt{x}\right)\right)$

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Final answer to the problem

$\frac{-1}{2\left(1+x\right)\sqrt{x}}$
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Step-by-step Solution

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Apply the formula: $\frac{d}{dx}\left(\mathrm{arccot}\left(\theta \right)\right)$$=\frac{-1}{1+\theta ^2}\frac{d}{dx}\left(\theta \right)$, where $x=\sqrt{x}$

$\frac{-1}{1+\left(\sqrt{x}\right)^2}\frac{d}{dx}\left(\sqrt{x}\right)$

Learn how to solve calcul différentiel problems step by step online.

$\frac{-1}{1+\left(\sqrt{x}\right)^2}\frac{d}{dx}\left(\sqrt{x}\right)$

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Learn how to solve calcul différentiel problems step by step online. d/dx(arccot(x^(1/2))). Apply the formula: \frac{d}{dx}\left(\mathrm{arccot}\left(\theta \right)\right)=\frac{-1}{1+\theta ^2}\frac{d}{dx}\left(\theta \right), where x=\sqrt{x}. Apply the formula: \left(x^a\right)^b=x, where a=\frac{1}{2}, b=2, x^a^b=\left(\sqrt{x}\right)^2 and x^a=\sqrt{x}. Apply the formula: \frac{d}{dx}\left(x^a\right)=ax^{\left(a-1\right)}, where a=\frac{1}{2}. Apply the formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, where a=-1, b=1+x, c=1, a/b=\frac{-1}{1+x}, f=2, c/f=\frac{1}{2} and a/bc/f=\frac{1}{2}\frac{-1}{1+x}x^{-\frac{1}{2}}.

Final answer to the problem

$\frac{-1}{2\left(1+x\right)\sqrt{x}}$

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Function Plot

Plotting: $\frac{-1}{2\left(1+x\right)\sqrt{x}}$

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6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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