Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choisir une option
- Produit de binômes avec terme commun
- Méthode FOIL
- Weierstrass Substitution
- Prouver à partir du LHS (côté gauche)
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We can factor the polynomial $x^3-x^2-6x$ using the rational root theorem, which guarantees that for a polynomial of the form $a_nx^n+a_{n-1}x^{n-1}+\dots+a_0$ there is a rational root of the form $\pm\frac{p}{q}$, where $p$ belongs to the divisors of the constant term $a_0$, and $q$ belongs to the divisors of the leading coefficient $a_n$. List all divisors $p$ of the constant term $a_0$, which equals $0$
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Learn how to solve factorisation polynomiale problems step by step online. x^3-x^2-6x. We can factor the polynomial x^3-x^2-6x using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals 0. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial x^3-x^2-6x will then be. We can factor the polynomial x^3-x^2-6x using synthetic division (Ruffini's rule). We found that -2 is a root of the polynomial.
