Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choisir une option
- Produit de binômes avec terme commun
- Méthode FOIL
- Weierstrass Substitution
- Prouver à partir du LHS (côté gauche)
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Apply the formula: $\frac{a}{b}$$=\frac{a}{b}\frac{conjugate\left(b\right)}{conjugate\left(b\right)}$, where $a=1$, $b=1+\sqrt{2}$ and $a/b=\frac{1}{1+\sqrt{2}}$
Learn how to solve rationalisation problems step by step online.
$\frac{1}{1+\sqrt{2}}\cdot \frac{1-\sqrt{2}}{1-\sqrt{2}}$
Learn how to solve rationalisation problems step by step online. Rationalize and simplify the expression 1/(1+2^(1/2)). Apply the formula: \frac{a}{b}=\frac{a}{b}\frac{conjugate\left(b\right)}{conjugate\left(b\right)}, where a=1, b=1+\sqrt{2} and a/b=\frac{1}{1+\sqrt{2}}. Apply the formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, where a=1, b=1+\sqrt{2}, c=1-\sqrt{2}, a/b=\frac{1}{1+\sqrt{2}}, f=1-\sqrt{2}, c/f=\frac{1-\sqrt{2}}{1-\sqrt{2}} and a/bc/f=\frac{1}{1+\sqrt{2}}\cdot \frac{1-\sqrt{2}}{1-\sqrt{2}}. Apply the formula: \left(a+b\right)\left(a+c\right)=a^2-b^2, where a=1, b=\sqrt{2}, c=-\sqrt{2}, a+c=1-\sqrt{2} and a+b=1+\sqrt{2}. Apply the formula: a+b=a+b, where a=1, b=-2 and a+b=1-2.
