Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choisir une option
- Produit de binômes avec terme commun
- Méthode FOIL
- Weierstrass Substitution
- Prouver à partir du LHS (côté gauche)
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Apply the formula: $\frac{a}{b}$$=\frac{a}{b}\frac{conjugate\left(b\right)}{conjugate\left(b\right)}$, where $a=1$, $b=2+\sqrt{3}$ and $a/b=\frac{1}{2+\sqrt{3}}$
Learn how to solve rationalisation problems step by step online.
$\frac{1}{2+\sqrt{3}}\cdot \frac{2-\sqrt{3}}{2-\sqrt{3}}$
Learn how to solve rationalisation problems step by step online. Rationalize and simplify the expression 1/(2+3^(1/2)). Apply the formula: \frac{a}{b}=\frac{a}{b}\frac{conjugate\left(b\right)}{conjugate\left(b\right)}, where a=1, b=2+\sqrt{3} and a/b=\frac{1}{2+\sqrt{3}}. Apply the formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, where a=1, b=2+\sqrt{3}, c=2-\sqrt{3}, a/b=\frac{1}{2+\sqrt{3}}, f=2-\sqrt{3}, c/f=\frac{2-\sqrt{3}}{2-\sqrt{3}} and a/bc/f=\frac{1}{2+\sqrt{3}}\cdot \frac{2-\sqrt{3}}{2-\sqrt{3}}. Apply the formula: \left(a+b\right)\left(a+c\right)=a^2-b^2, where a=2, b=\sqrt{3}, c=-\sqrt{3}, a+c=2-\sqrt{3} and a+b=2+\sqrt{3}. Apply the formula: a+b=a+b, where a=4, b=-3 and a+b=4-3.
