$\frac{64a^3+343}{4a+7}$

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Final answer to the problem

$16a^{2}-28a+49$
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Apply the formula: $a+b$$=\left(\sqrt[3]{a}+\sqrt[3]{\left|b\right|}\right)\left(\sqrt[3]{a^{2}}-\sqrt[3]{a}\sqrt[3]{\left|b\right|}+\sqrt[3]{\left|b\right|^{2}}\right)$, where $a=64a^3$ and $b=343$

$\frac{\left(\sqrt[3]{64a^3}+\sqrt[3]{343}\right)\left(\sqrt[3]{\left(64a^3\right)^{2}}-\sqrt[3]{343}\sqrt[3]{64a^3}+\sqrt[3]{\left(343\right)^{2}}\right)}{4a+7}$

Learn how to solve calcul intégral problems step by step online.

$\frac{\left(\sqrt[3]{64a^3}+\sqrt[3]{343}\right)\left(\sqrt[3]{\left(64a^3\right)^{2}}-\sqrt[3]{343}\sqrt[3]{64a^3}+\sqrt[3]{\left(343\right)^{2}}\right)}{4a+7}$

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Learn how to solve calcul intégral problems step by step online. (64a^3+343)/(4a+7). Apply the formula: a+b=\left(\sqrt[3]{a}+\sqrt[3]{\left|b\right|}\right)\left(\sqrt[3]{a^{2}}-\sqrt[3]{a}\sqrt[3]{\left|b\right|}+\sqrt[3]{\left|b\right|^{2}}\right), where a=64a^3 and b=343. Apply the formula: a^b=a^b, where a=343, b=\frac{1}{3} and a^b=\sqrt[3]{343}. Apply the formula: a^b=a^b, where a=343, b=\frac{1}{3} and a^b=\sqrt[3]{343}. Apply the formula: ab=ab, where ab=- 7\sqrt[3]{64a^3}, a=-1 and b=7.

Final answer to the problem

$16a^{2}-28a+49$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Calcul intégral

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