$\frac{216-125y^3}{6-5y}$

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Final answer to the problem

$\frac{\left(6+5y\right)\left(36-30y+25y^{2}\right)}{6-5y}$
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Step-by-step Solution

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Apply the formula: $a+b$$=\left(\sqrt[3]{a}+\sqrt[3]{\left|b\right|}\right)\left(\sqrt[3]{a^{2}}-\sqrt[3]{a}\sqrt[3]{\left|b\right|}+\sqrt[3]{\left|b\right|^{2}}\right)$, where $a=216$ and $b=-125y^3$

$\frac{\left(\sqrt[3]{216}+\sqrt[3]{125y^3}\right)\left(\sqrt[3]{\left(216\right)^{2}}-\sqrt[3]{216}\sqrt[3]{125y^3}+\sqrt[3]{\left(125y^3\right)^{2}}\right)}{6-5y}$

Learn how to solve division polynomiale longue problems step by step online.

$\frac{\left(\sqrt[3]{216}+\sqrt[3]{125y^3}\right)\left(\sqrt[3]{\left(216\right)^{2}}-\sqrt[3]{216}\sqrt[3]{125y^3}+\sqrt[3]{\left(125y^3\right)^{2}}\right)}{6-5y}$

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Learn how to solve division polynomiale longue problems step by step online. (216-125y^3)/(6-5y). Apply the formula: a+b=\left(\sqrt[3]{a}+\sqrt[3]{\left|b\right|}\right)\left(\sqrt[3]{a^{2}}-\sqrt[3]{a}\sqrt[3]{\left|b\right|}+\sqrt[3]{\left|b\right|^{2}}\right), where a=216 and b=-125y^3. Apply the formula: a^b=a^b, where a=216, b=\frac{1}{3} and a^b=\sqrt[3]{216}. Apply the formula: a^b=a^b, where a=216, b=\frac{2}{3} and a^b=\sqrt[3]{\left(216\right)^{2}}. Apply the formula: ab=ab, where ab=- 6\sqrt[3]{125y^3}, a=-1 and b=6.

Final answer to the problem

$\frac{\left(6+5y\right)\left(36-30y+25y^{2}\right)}{6-5y}$

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Plotting: $\frac{\left(6+5y\right)\left(36-30y+25y^{2}\right)}{6-5y}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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