Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choisir une option
- Produit de binômes avec terme commun
- Méthode FOIL
- Weierstrass Substitution
- Prouver à partir du LHS (côté gauche)
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Apply the formula: $\frac{a}{b}$$=\frac{a}{b}\frac{conjugate\left(b\right)}{conjugate\left(b\right)}$, where $a=3$, $b=2-\sqrt{5}$ and $a/b=\frac{3}{2-\sqrt{5}}$
Learn how to solve rationalisation problems step by step online.
$\frac{3}{2-\sqrt{5}}\cdot \frac{2+\sqrt{5}}{2+\sqrt{5}}$
Learn how to solve rationalisation problems step by step online. Rationalize and simplify the expression 3/(2-5^(1/2)). Apply the formula: \frac{a}{b}=\frac{a}{b}\frac{conjugate\left(b\right)}{conjugate\left(b\right)}, where a=3, b=2-\sqrt{5} and a/b=\frac{3}{2-\sqrt{5}}. Apply the formula: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, where a=3, b=2-\sqrt{5}, c=2+\sqrt{5}, a/b=\frac{3}{2-\sqrt{5}}, f=2+\sqrt{5}, c/f=\frac{2+\sqrt{5}}{2+\sqrt{5}} and a/bc/f=\frac{3}{2-\sqrt{5}}\cdot \frac{2+\sqrt{5}}{2+\sqrt{5}}. Apply the formula: \left(a+b\right)\left(a+c\right)=a^2-b^2, where a=2, b=\sqrt{5}, c=-\sqrt{5}, a+c=2+\sqrt{5} and a+b=2-\sqrt{5}. Apply the formula: a+b=a+b, where a=4, b=-5 and a+b=4-5.
