$y^{\prime}+y=e^{2x}$

Got another answer? Verify it here!

Learn how to solve discriminant d'une équation quadratique problems step by step online.

$\frac{dy}{dx}+y=e^{2x}$

Learn how to solve discriminant d'une équation quadratique problems step by step online. y^'+y=e^(2x). Rewrite the differential equation using Leibniz notation. We can identify that the differential equation has the form: \frac{dy}{dx} + P(x)\cdot y(x) = Q(x), so we can classify it as a linear first order differential equation, where P(x)=1 and Q(x)=e^{2x}. In order to solve the differential equation, the first step is to find the integrating factor \mu(x). To find \mu(x), we first need to calculate \int P(x)dx. So the integrating factor \mu(x) is.