$x^2y^{\prime}=4x^2+7xy+2y^2$

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Final answer to the problem

$-\frac{1}{2}\ln\left(\frac{y}{x}+2\right)+\frac{1}{2}\ln\left(\frac{y}{x}+1\right)=\ln\left(x\right)+C_0$
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Step-by-step Solution

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Rewrite the differential equation using Leibniz notation

$x^2\frac{dy}{dx}=4x^2+7xy+2y^2$

Learn how to solve equations différentielles problems step by step online.

$x^2\frac{dy}{dx}=4x^2+7xy+2y^2$

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Learn how to solve equations différentielles problems step by step online. x^2y^'=4x^2+7xy2y^2. Rewrite the differential equation using Leibniz notation. Apply the formula: a\frac{dy}{dx}=c\to \frac{dy}{dx}=\frac{c}{a}, where a=x^2 and c=4x^2+7xy+2y^2. We can identify that the differential equation \frac{dy}{dx}=\frac{4x^2+7xy+2y^2}{x^2} is homogeneous, since it is written in the standard form \frac{dy}{dx}=\frac{M(x,y)}{N(x,y)}, where M(x,y) and N(x,y) are the partial derivatives of a two-variable function f(x,y) and both are homogeneous functions of the same degree. Use the substitution: y=ux.

Final answer to the problem

$-\frac{1}{2}\ln\left(\frac{y}{x}+2\right)+\frac{1}{2}\ln\left(\frac{y}{x}+1\right)=\ln\left(x\right)+C_0$

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Function Plot

Plotting: $-\frac{1}{2}\ln\left(\frac{y}{x}+2\right)+\frac{1}{2}\ln\left(\frac{y}{x}+1\right)=\ln\left(x\right)+C_0$

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7
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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Equations différentielles

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