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$f\left(x\right)=\left(4x+1\right)\left(6x+3\right)$

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Solution

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Final answer to the problem

$f\left(x\right)=3\left(4x+1\right)\left(2x+1\right)$
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Factor the polynomial $\left(6x+3\right)$ by it's greatest common factor (GCF): $3$

$f\left(x\right)=3\left(4x+1\right)\left(2x+1\right)$

Final answer to the problem

$f\left(x\right)=3\left(4x+1\right)\left(2x+1\right)$

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Function Plot

Plotting: $f\left(x\right)-\left(4x+1\right)\left(6x+3\right)$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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$f\left(x\right)=\left(4x+1\right)\left(6x+3\right)$

$f\left(x\right)=\frac{1}{\left(1+x\right)^2}$

$f\left(x\right)=x^2-4x$

$f\left(x\right)=x^{\frac{4}{3}}$

Main Topic: Expressions algébriques

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