Exercice
$\left(-2x^2-3x^3-2x+3\right):\left(x^2-2x+2\right)$
Solution étape par étape
1
Diviser $-2x^2-3x^3-2x+3$ par $x^2-2x+2$
$\begin{array}{l}\phantom{\phantom{;}x^{2}-2x\phantom{;}+2;}{-3x\phantom{;}-8\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-2x\phantom{;}+2\overline{\smash{)}-3x^{3}-2x^{2}-2x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-2x\phantom{;}+2;}\underline{\phantom{;}3x^{3}-6x^{2}+6x\phantom{;}\phantom{-;x^n}}\\\phantom{\phantom{;}3x^{3}-6x^{2}+6x\phantom{;};}-8x^{2}+4x\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-2x\phantom{;}+2-;x^n;}\underline{\phantom{;}8x^{2}-16x\phantom{;}+16\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}8x^{2}-16x\phantom{;}+16\phantom{;}\phantom{;}-;x^n;}-12x\phantom{;}+19\phantom{;}\phantom{;}\\\end{array}$
$-3x-8+\frac{-12x+19}{x^2-2x+2}$
Réponse finale au problème
$-3x-8+\frac{-12x+19}{x^2-2x+2}$