Exercice
$\frac{8c^2-c+19c^3+15c^4-1}{5c^3-3c-1}$
Solution étape par étape
1
Diviser $8c^2-c+19c^3+15c^4-1$ par $5c^3-3c-1$
$\begin{array}{l}\phantom{\phantom{;}5c^{3}-3c\phantom{;}-1;}{\phantom{;}3c\phantom{;}+\frac{19}{5}\phantom{;}\phantom{;}}\\\phantom{;}5c^{3}-3c\phantom{;}-1\overline{\smash{)}\phantom{;}15c^{4}+19c^{3}+8c^{2}-c\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}5c^{3}-3c\phantom{;}-1;}\underline{-15c^{4}\phantom{-;x^n}+9c^{2}+3c\phantom{;}\phantom{-;x^n}}\\\phantom{-15c^{4}+9c^{2}+3c\phantom{;};}\phantom{;}19c^{3}+17c^{2}+2c\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}5c^{3}-3c\phantom{;}-1-;x^n;}\underline{-19c^{3}\phantom{-;x^n}+\frac{57}{5}c\phantom{;}+\frac{19}{5}\phantom{;}\phantom{;}}\\\phantom{;-19c^{3}+\frac{57}{5}c\phantom{;}+\frac{19}{5}\phantom{;}\phantom{;}-;x^n;}\phantom{;}17c^{2}+\frac{67}{5}c\phantom{;}+\frac{14}{5}\phantom{;}\phantom{;}\\\end{array}$
$3c+\frac{19}{5}+\frac{17c^{2}+\frac{67}{5}c+\frac{14}{5}}{5c^3-3c-1}$
Réponse finale au problème
$3c+\frac{19}{5}+\frac{17c^{2}+\frac{67}{5}c+\frac{14}{5}}{5c^3-3c-1}$