Exercice
$\frac{4x^3+8x^2+7x+7}{2x+3}$
Solution étape par étape
1
Diviser $4x^3+8x^2+7x+7$ par $2x+3$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+3;}{\phantom{;}2x^{2}+x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+3\overline{\smash{)}\phantom{;}4x^{3}+8x^{2}+7x\phantom{;}+7\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+3;}\underline{-4x^{3}-6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-4x^{3}-6x^{2};}\phantom{;}2x^{2}+7x\phantom{;}+7\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n;}\underline{-2x^{2}-3x\phantom{;}\phantom{-;x^n}}\\\phantom{;-2x^{2}-3x\phantom{;}-;x^n;}\phantom{;}4x\phantom{;}+7\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+3-;x^n-;x^n;}\underline{-4x\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{;;-4x\phantom{;}-6\phantom{;}\phantom{;}-;x^n-;x^n;}\phantom{;}1\phantom{;}\phantom{;}\\\end{array}$
$2x^{2}+x+2+\frac{1}{2x+3}$
Réponse finale au problème
$2x^{2}+x+2+\frac{1}{2x+3}$