Exercice
$\frac{3x^4-x^3-6x^2+29x-9}{3x-1}$
Solution étape par étape
1
Diviser $3x^4-x^3-6x^2+29x-9$ par $3x-1$
$\begin{array}{l}\phantom{\phantom{;}3x\phantom{;}-1;}{\phantom{;}x^{3}\phantom{-;x^n}-2x\phantom{;}+9\phantom{;}\phantom{;}}\\\phantom{;}3x\phantom{;}-1\overline{\smash{)}\phantom{;}3x^{4}-x^{3}-6x^{2}+29x\phantom{;}-9\phantom{;}\phantom{;}}\\\phantom{\phantom{;}3x\phantom{;}-1;}\underline{-3x^{4}+x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3x^{4}+x^{3};}-6x^{2}+29x\phantom{;}-9\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x\phantom{;}-1-;x^n;}\underline{\phantom{;}6x^{2}-2x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}6x^{2}-2x\phantom{;}-;x^n;}\phantom{;}27x\phantom{;}-9\phantom{;}\phantom{;}\\\phantom{\phantom{;}3x\phantom{;}-1-;x^n-;x^n;}\underline{-27x\phantom{;}+9\phantom{;}\phantom{;}}\\\phantom{;;-27x\phantom{;}+9\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Réponse finale au problème
$x^{3}-2x+9$