Exercice
$\frac{3x^4-2x^3-10x^2-2x-6}{x+1}$
Solution étape par étape
1
Diviser $3x^4-2x^3-10x^2-2x-6$ par $x+1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+1;}{\phantom{;}3x^{3}-5x^{2}-5x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+1\overline{\smash{)}\phantom{;}3x^{4}-2x^{3}-10x^{2}-2x\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+1;}\underline{-3x^{4}-3x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3x^{4}-3x^{3};}-5x^{3}-10x^{2}-2x\phantom{;}-6\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n;}\underline{\phantom{;}5x^{3}+5x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}5x^{3}+5x^{2}-;x^n;}-5x^{2}-2x\phantom{;}-6\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n;}\underline{\phantom{;}5x^{2}+5x\phantom{;}\phantom{-;x^n}}\\\phantom{;;\phantom{;}5x^{2}+5x\phantom{;}-;x^n-;x^n;}\phantom{;}3x\phantom{;}-6\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n-;x^n;}\underline{-3x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;;;-3x\phantom{;}-3\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}-9\phantom{;}\phantom{;}\\\end{array}$
$3x^{3}-5x^{2}-5x+3+\frac{-9}{x+1}$
Réponse finale au problème
$3x^{3}-5x^{2}-5x+3+\frac{-9}{x+1}$