Exercice
$\frac{3x^3-2x^4-1-x^2}{x-2}$
Solution étape par étape
1
Diviser $3x^3-2x^4-1-x^2$ par $x-2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-2;}{-2x^{3}-x^{2}-3x\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-2\overline{\smash{)}-2x^{4}+3x^{3}-x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-2;}\underline{\phantom{;}2x^{4}-4x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}2x^{4}-4x^{3};}-x^{3}-x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n;}\underline{\phantom{;}x^{3}-2x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}x^{3}-2x^{2}-;x^n;}-3x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n;}\underline{\phantom{;}3x^{2}-6x\phantom{;}\phantom{-;x^n}}\\\phantom{;;\phantom{;}3x^{2}-6x\phantom{;}-;x^n-;x^n;}-6x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n-;x^n;}\underline{\phantom{;}6x\phantom{;}-12\phantom{;}\phantom{;}}\\\phantom{;;;\phantom{;}6x\phantom{;}-12\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}-13\phantom{;}\phantom{;}\\\end{array}$
$-2x^{3}-x^{2}-3x-6+\frac{-13}{x-2}$
Réponse finale au problème
$-2x^{3}-x^{2}-3x-6+\frac{-13}{x-2}$