Exercice
$\frac{3n^4+n^3-7n^2-2n+2}{n^2-2}$
Solution étape par étape
1
Diviser $3n^4+n^3-7n^2-2n+2$ par $n^2-2$
$\begin{array}{l}\phantom{\phantom{;}n^{2}-2;}{\phantom{;}3n^{2}+n\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{;}n^{2}-2\overline{\smash{)}\phantom{;}3n^{4}+n^{3}-7n^{2}-2n\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}n^{2}-2;}\underline{-3n^{4}\phantom{-;x^n}+6n^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3n^{4}+6n^{2};}\phantom{;}n^{3}-n^{2}-2n\phantom{;}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}n^{2}-2-;x^n;}\underline{-n^{3}\phantom{-;x^n}+2n\phantom{;}\phantom{-;x^n}}\\\phantom{;-n^{3}+2n\phantom{;}-;x^n;}-n^{2}\phantom{-;x^n}+2\phantom{;}\phantom{;}\\\phantom{\phantom{;}n^{2}-2-;x^n-;x^n;}\underline{\phantom{;}n^{2}\phantom{-;x^n}-2\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}n^{2}-2\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Réponse finale au problème
$3n^{2}+n-1$