Exercice
$\frac{2x^4+x^2+8}{x+1}$
Solution étape par étape
1
Diviser $2x^4+x^2+8$ par $x+1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+1;}{\phantom{;}2x^{3}-2x^{2}+3x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+1\overline{\smash{)}\phantom{;}2x^{4}\phantom{-;x^n}+x^{2}\phantom{-;x^n}+8\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+1;}\underline{-2x^{4}-2x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-2x^{4}-2x^{3};}-2x^{3}+x^{2}\phantom{-;x^n}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n;}\underline{\phantom{;}2x^{3}+2x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}2x^{3}+2x^{2}-;x^n;}\phantom{;}3x^{2}\phantom{-;x^n}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n;}\underline{-3x^{2}-3x\phantom{;}\phantom{-;x^n}}\\\phantom{;;-3x^{2}-3x\phantom{;}-;x^n-;x^n;}-3x\phantom{;}+8\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n-;x^n;}\underline{\phantom{;}3x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;;;\phantom{;}3x\phantom{;}+3\phantom{;}\phantom{;}-;x^n-;x^n-;x^n;}\phantom{;}11\phantom{;}\phantom{;}\\\end{array}$
$2x^{3}-2x^{2}+3x-3+\frac{11}{x+1}$
Réponse finale au problème
$2x^{3}-2x^{2}+3x-3+\frac{11}{x+1}$