Exercice
$\frac{-2x^4+11x^3+6x^2+x+3}{x-6}$
Solution étape par étape
1
Diviser $-2x^4+11x^3+6x^2+x+3$ par $x-6$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-6;}{-2x^{3}-x^{2}\phantom{-;x^n}+1\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-6\overline{\smash{)}-2x^{4}+11x^{3}+6x^{2}+x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-6;}\underline{\phantom{;}2x^{4}-12x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{\phantom{;}2x^{4}-12x^{3};}-x^{3}+6x^{2}+x\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-6-;x^n;}\underline{\phantom{;}x^{3}-6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}x^{3}-6x^{2}-;x^n;}\phantom{;}x\phantom{;}+3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-6-;x^n-;x^n;}\underline{-x\phantom{;}+6\phantom{;}\phantom{;}}\\\phantom{;;-x\phantom{;}+6\phantom{;}\phantom{;}-;x^n-;x^n;}\phantom{;}9\phantom{;}\phantom{;}\\\end{array}$
$-2x^{3}-x^{2}+1+\frac{9}{x-6}$
Réponse finale au problème
$-2x^{3}-x^{2}+1+\frac{9}{x-6}$