Exercice
$\frac{\left(y^3-3y^2+2y-2\right)}{y+1}$
Solution étape par étape
1
Diviser $y^3-3y^2+2y-2$ par $y+1$
$\begin{array}{l}\phantom{\phantom{;}y\phantom{;}+1;}{\phantom{;}y^{2}-4y\phantom{;}+6\phantom{;}\phantom{;}}\\\phantom{;}y\phantom{;}+1\overline{\smash{)}\phantom{;}y^{3}-3y^{2}+2y\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}y\phantom{;}+1;}\underline{-y^{3}-y^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-y^{3}-y^{2};}-4y^{2}+2y\phantom{;}-2\phantom{;}\phantom{;}\\\phantom{\phantom{;}y\phantom{;}+1-;x^n;}\underline{\phantom{;}4y^{2}+4y\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}4y^{2}+4y\phantom{;}-;x^n;}\phantom{;}6y\phantom{;}-2\phantom{;}\phantom{;}\\\phantom{\phantom{;}y\phantom{;}+1-;x^n-;x^n;}\underline{-6y\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{;;-6y\phantom{;}-6\phantom{;}\phantom{;}-;x^n-;x^n;}-8\phantom{;}\phantom{;}\\\end{array}$
$y^{2}-4y+6+\frac{-8}{y+1}$
Réponse finale au problème
$y^{2}-4y+6+\frac{-8}{y+1}$