Exercice
$\frac{\left(6x^2+47x+32\right)}{\left(x+7\right)}$
Solution étape par étape
1
Diviser $6x^2+47x+32$ par $x+7$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+7;}{\phantom{;}6x\phantom{;}+5\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+7\overline{\smash{)}\phantom{;}6x^{2}+47x\phantom{;}+32\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+7;}\underline{-6x^{2}-42x\phantom{;}\phantom{-;x^n}}\\\phantom{-6x^{2}-42x\phantom{;};}\phantom{;}5x\phantom{;}+32\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+7-;x^n;}\underline{-5x\phantom{;}-35\phantom{;}\phantom{;}}\\\phantom{;-5x\phantom{;}-35\phantom{;}\phantom{;}-;x^n;}-3\phantom{;}\phantom{;}\\\end{array}$
$6x+5+\frac{-3}{x+7}$
Réponse finale au problème
$6x+5+\frac{-3}{x+7}$