Exercice
$\frac{\left(3x^3-4\right)}{\left(x+1\right)}$
Solution étape par étape
1
Diviser $3x^3-4$ par $x+1$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+1;}{\phantom{;}3x^{2}-3x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+1\overline{\smash{)}\phantom{;}3x^{3}\phantom{-;x^n}\phantom{-;x^n}-4\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+1;}\underline{-3x^{3}-3x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-3x^{3}-3x^{2};}-3x^{2}\phantom{-;x^n}-4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n;}\underline{\phantom{;}3x^{2}+3x\phantom{;}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{2}+3x\phantom{;}-;x^n;}\phantom{;}3x\phantom{;}-4\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+1-;x^n-;x^n;}\underline{-3x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;;-3x\phantom{;}-3\phantom{;}\phantom{;}-;x^n-;x^n;}-7\phantom{;}\phantom{;}\\\end{array}$
$3x^{2}-3x+3+\frac{-7}{x+1}$
Réponse finale au problème
$3x^{2}-3x+3+\frac{-7}{x+1}$