Exercice
$\frac{\left(20x^4+6x^3-2x^2+15x-2\right)}{5x-1}$
Solution étape par étape
1
Diviser $20x^4+6x^3-2x^2+15x-2$ par $5x-1$
$\begin{array}{l}\phantom{\phantom{;}5x\phantom{;}-1;}{\phantom{;}4x^{3}+2x^{2}\phantom{-;x^n}+3\phantom{;}\phantom{;}}\\\phantom{;}5x\phantom{;}-1\overline{\smash{)}\phantom{;}20x^{4}+6x^{3}-2x^{2}+15x\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}5x\phantom{;}-1;}\underline{-20x^{4}+4x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-20x^{4}+4x^{3};}\phantom{;}10x^{3}-2x^{2}+15x\phantom{;}-2\phantom{;}\phantom{;}\\\phantom{\phantom{;}5x\phantom{;}-1-;x^n;}\underline{-10x^{3}+2x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;-10x^{3}+2x^{2}-;x^n;}\phantom{;}15x\phantom{;}-2\phantom{;}\phantom{;}\\\phantom{\phantom{;}5x\phantom{;}-1-;x^n-;x^n;}\underline{-15x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;;-15x\phantom{;}+3\phantom{;}\phantom{;}-;x^n-;x^n;}\phantom{;}1\phantom{;}\phantom{;}\\\end{array}$
$4x^{3}+2x^{2}+3+\frac{1}{5x-1}$
Réponse finale au problème
$4x^{3}+2x^{2}+3+\frac{1}{5x-1}$