Exercice
$\frac{\left(12x^4+2x^3+x-3\right)}{\left(2x^2+1\right)}$
Solution étape par étape
1
Diviser $12x^4+2x^3+x-3$ par $2x^2+1$
$\begin{array}{l}\phantom{\phantom{;}2x^{2}+1;}{\phantom{;}6x^{2}+x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}2x^{2}+1\overline{\smash{)}\phantom{;}12x^{4}+2x^{3}\phantom{-;x^n}+x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x^{2}+1;}\underline{-12x^{4}\phantom{-;x^n}-6x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-12x^{4}-6x^{2};}\phantom{;}2x^{3}-6x^{2}+x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x^{2}+1-;x^n;}\underline{-2x^{3}\phantom{-;x^n}-x\phantom{;}\phantom{-;x^n}}\\\phantom{;-2x^{3}-x\phantom{;}-;x^n;}-6x^{2}\phantom{-;x^n}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x^{2}+1-;x^n-;x^n;}\underline{\phantom{;}6x^{2}\phantom{-;x^n}+3\phantom{;}\phantom{;}}\\\phantom{;;\phantom{;}6x^{2}+3\phantom{;}\phantom{;}-;x^n-;x^n;}\\\end{array}$
Réponse finale au problème
$6x^{2}+x-3$