Final answer to the problem
$x=-5,\:x=-6$
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1
Factor the trinomial $x^2+11x+30$ finding two numbers that multiply to form $30$ and added form $11$
$\begin{matrix}\left(5\right)\left(6\right)=30\\ \left(5\right)+\left(6\right)=11\end{matrix}$
Learn how to solve equations quadratiques problems step by step online.
$\begin{matrix}\left(5\right)\left(6\right)=30\\ \left(5\right)+\left(6\right)=11\end{matrix}$
Learn how to solve equations quadratiques problems step by step online. Solve the quadratic equation x^2+11x+30=0. Factor the trinomial x^2+11x+30 finding two numbers that multiply to form 30 and added form 11. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Break the equation in 2 factors and set each factor equal to zero, to obtain simpler equations. Solve the equation (1).
Final answer to the problem
$x=-5,\:x=-6$
