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Apply the formula: $x^2+bx+c=0$$\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}$, where $b=-18$, $c=81$, $bx=-18x$, $x^2+bx=x^2-18x+81$ and $x^2+bx=0=x^2-18x+81=0$
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$x=\frac{18\pm \sqrt{{\left(-18\right)}^2-4\cdot 81}}{2}$
Learn how to solve equations quadratiques problems step by step online. Solve the quadratic equation x^2-18x+81=0. Apply the formula: x^2+bx+c=0\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}, where b=-18, c=81, bx=-18x, x^2+bx=x^2-18x+81 and x^2+bx=0=x^2-18x+81=0. Apply the formula: a=b\to a=b, where a=x and b=\frac{18\pm \sqrt{{\left(-18\right)}^2-4\cdot 81}}{2}. Apply the formula: x=\frac{b\pm c}{f}\to x=\frac{b+c}{f},\:x=\frac{b-c}{f}, where b=18, c=0 and f=2. Apply the formula: a+b=a+b, where a=18, b=0 and a+b=18+0.
