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Apply the formula: $x^2+bx+c=0$$\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}$, where $b=-1$, $c=5$, $bx=-x$, $x^2+bx=x^2-x+5$ and $x^2+bx=0=x^2-x+5=0$
Learn how to solve equations quadratiques problems step by step online.
$x=\frac{- -1\pm \sqrt{{\left(-1\right)}^2-4\cdot 5}}{2}$
Learn how to solve equations quadratiques problems step by step online. Solve the quadratic equation x^2-x+5=0. Apply the formula: x^2+bx+c=0\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}, where b=-1, c=5, bx=-x, x^2+bx=x^2-x+5 and x^2+bx=0=x^2-x+5=0. Apply the formula: a=b\to a=b, where a=x and b=\frac{- -1\pm \sqrt{{\left(-1\right)}^2-4\cdot 5}}{2}. Apply the formula: x=\frac{b\pm c}{f}\to x=\frac{b+c}{f},\:x=\frac{b-c}{f}, where b=1, c=\sqrt{19}i and f=2. Combining all solutions, the 2 solutions of the equation are.
