Final answer to the problem
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
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1
Apply the formula: $\left(x+a\right)\left(x+b\right)$$=x^2+\left(a+b\right)x+ab$, where $a=-1$, $b=4$, $x+b=x+4$ and $x+a=x-1$
$i\left(x\right)=x\left(x^2+\left(-1+4\right)x-4\right)\left(x-2\right)$
2
Apply the formula: $a+b$$=a+b$, where $a=4$, $b=-1$ and $a+b=-1+4$
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
Final answer to the problem
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
