R�ponse finale au probl�me
Solution �tape par �tape
Comment r�soudre ce probl�me ?
- Choisir une option
- Produit de binômes avec terme commun
- Méthode FOIL
- Weierstrass Substitution
- Prouver à partir du LHS (côté gauche)
- En savoir plus...
We can factor the polynomial $x^3-7x+6$ using the rational root theorem, which guarantees that for a polynomial of the form $a_nx^n+a_{n-1}x^{n-1}+\dots+a_0$ there is a rational root of the form $\pm\frac{p}{q}$, where $p$ belongs to the divisors of the constant term $a_0$, and $q$ belongs to the divisors of the leading coefficient $a_n$. List all divisors $p$ of the constant term $a_0$, which equals $6$
Apprenez en ligne à résoudre des problèmes factorisation étape par étape.
$1, 2, 3, 6$
Apprenez en ligne à résoudre des problèmes factorisation étape par étape. x^3-7x+6. We can factor the polynomial x^3-7x+6 using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals 6. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial x^3-7x+6 will then be. Trying all possible roots, we found that -3 is a root of the polynomial. When we evaluate it in the polynomial, it gives us 0 as a result.
