Final answer to the problem
$y=\frac{1}{3}\ln\left(\frac{x-1}{x+1}\right)$
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Apply the formula: $\ln\left(x^a\right)$$=a\ln\left(x\right)$, where $a=\frac{1}{3}$ and $x=\frac{x-1}{x+1}$
$y=\frac{1}{3}\ln\left(\frac{x-1}{x+1}\right)$
Final answer to the problem
$y=\frac{1}{3}\ln\left(\frac{x-1}{x+1}\right)$
