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Apply the formula: $x^2+bx$$=x^2+bx+\left(\frac{b}{2}\right)^2-\left(\frac{b}{2}\right)^2$, where $b=-6$, $bx=-6x$ and $x^2+bx=x^2-6x$
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$x^2-6x+9-9=8$
Learn how to solve problems step by step online. Solve the quadratic equation x^2-6x=8. Apply the formula: x^2+bx=x^2+bx+\left(\frac{b}{2}\right)^2-\left(\frac{b}{2}\right)^2, where b=-6, bx=-6x and x^2+bx=x^2-6x. Apply the formula: x^2+bx+f+g=\left(x+\sqrt{f}sign\left(b\right)\right)^2+g, where b=-6, bx=-6x, f=9, g=-9 and x^2+bx=x^2-6x+9-9. Apply the formula: x+a=b\to x+a-a=b-a, where a=-9, b=8, x+a=b=\left(x-3\right)^2-9=8, x=\left(x-3\right)^2 and x+a=\left(x-3\right)^2-9. Apply the formula: x+a+c=b+f\to x=b-a, where a=-9, b=8, c=9, f=9 and x=\left(x-3\right)^2.
