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Apply the formula: $x^2+bx+c=0$$\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}$, where $b=-32$, $c=256$, $bx=-32x$, $x^2+bx=x^2-32x+256$ and $x^2+bx=0=x^2-32x+256=0$
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$x=\frac{32\pm \sqrt{{\left(-32\right)}^2-4\cdot 256}}{2}$
Learn how to solve equations quadratiques problems step by step online. Solve the quadratic equation x^2-32x+256=0. Apply the formula: x^2+bx+c=0\to x=\frac{-b\pm \sqrt{b^2-4c}}{2}, where b=-32, c=256, bx=-32x, x^2+bx=x^2-32x+256 and x^2+bx=0=x^2-32x+256=0. Apply the formula: a=b\to a=b, where a=x and b=\frac{32\pm \sqrt{{\left(-32\right)}^2-4\cdot 256}}{2}. Apply the formula: x=\frac{b\pm c}{f}\to x=\frac{b+c}{f},\:x=\frac{b-c}{f}, where b=32, c=0 and f=2. Apply the formula: a+b=a+b, where a=32, b=0 and a+b=32+0.
