Final answer to the problem
$y=\left(9-x^{0.5}\right)^{\frac{1}{0,5}}$
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Step-by-step Solution
How should I solve this problem?
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- Résoudre pour x
- Résoudre pour y
- Solve for y'
- Find dy/dx
- Derivative
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1
Apply the formula: $x+a=b$$\to x=b-a$, where $a=x^{0.5}$, $b=9$, $x+a=b=x^{0.5}+y^{\left(0,5\right)}=9$, $x=y^{\left(0,5\right)}$ and $x+a=x^{0.5}+y^{\left(0,5\right)}$
$y^{\left(0,5\right)}=9-x^{0.5}$
2
Apply the formula: $y^a=b$$\to y=b^{\frac{sign\left(a\right)}{\left|a\right|}}$, where $a=0,5$ and $b=9-x^{0.5}$
$y=\left(9-x^{0.5}\right)^{\frac{1}{0,5}}$
Final answer to the problem
$y=\left(9-x^{0.5}\right)^{\frac{1}{0,5}}$
