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Move the term with the square root to the left side of the equation, and all other terms to the right side. Remember to change the signs of each term
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$\sqrt{x+1}=8-2x$
Learn how to solve produits spéciaux problems step by step online. 2x+(x+1)^(1/2)=8. Move the term with the square root to the left side of the equation, and all other terms to the right side. Remember to change the signs of each term. Apply the formula: x^a=b\to \left(x^a\right)^{inverse\left(a\right)}=b^{inverse\left(a\right)}, where a=\frac{1}{2}, b=8-2x, x^a=b=\sqrt{x+1}=8-2x, x=x+1 and x^a=\sqrt{x+1}. Factor the polynomial \left(8-2x\right) by it's greatest common factor (GCF): 2. Apply the formula: \left(ab\right)^n=a^nb^n.