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Apply the formula: $a^x=b$$\to \log_{a}\left(a^x\right)=\log_{a}\left(b\right)$, where $a=26$, $b=1$ and $x=9x+5$
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$\log_{26}\left(26^{\left(9x+5\right)}\right)=\log_{26}\left(1\right)$
Learn how to solve equations exponentielles problems step by step online. Solve the exponential equation 26^(9x+5)=1. Apply the formula: a^x=b\to \log_{a}\left(a^x\right)=\log_{a}\left(b\right), where a=26, b=1 and x=9x+5. Apply the formula: \log_{a}\left(b\right)=logf\left(b,a\right), where a=26, b=1 and a,b=26,1. Apply the formula: \log_{b}\left(b^a\right)=a, where a=9x+5 and b=26. Apply the formula: x+a=b\to x+a-a=b-a, where a=5, b=0, x+a=b=9x+5=0, x=9x and x+a=9x+5.
