$\log_{9}\left(x-5\right)+\log_{9}\left(x+3\right)=1$

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Final answer to the problem

$x=6$
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Express the numbers in the equation as logarithms of base $9$

$\log_{9}\left(x-5\right)+\log_{9}\left(x+3\right)=\log_{9}\left(9^{1}\right)$

Learn how to solve equations logarithmiques problems step by step online.

$\log_{9}\left(x-5\right)+\log_{9}\left(x+3\right)=\log_{9}\left(9^{1}\right)$

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Learn how to solve equations logarithmiques problems step by step online. log9(x+-5)+log9(x+3)=1. Express the numbers in the equation as logarithms of base 9. Apply the formula: x^1=x, where x=9. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=9, x=x-5 and y=x+3. Apply the formula: \log_{a}\left(x\right)=\log_{a}\left(y\right)\to x=y, where a=9, x=\left(x-5\right)\left(x+3\right) and y=9.

Final answer to the problem

$x=6$

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Function Plot

Plotting: $\log_{9}\left(x-5\right)+\log_{9}\left(x+3\right)-1$

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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