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Express the numbers in the equation as logarithms of base $5$
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$\log_{5}\left(x\right)+\log_{5}\left(4x-1\right)=\log_{5}\left(5^{1}\right)$
Learn how to solve problems step by step online. log5(x)+log5(4*x+-1)=1. Express the numbers in the equation as logarithms of base 5. Apply the formula: x^1=x, where x=5. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=5 and y=4x-1. Apply the formula: \log_{a}\left(x\right)=\log_{a}\left(y\right)\to x=y, where a=5, x=x\left(4x-1\right) and y=5.