Final answer to the problem
$x=16$
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1
Express the numbers in the equation as logarithms of base $4$
$\log_{4}\left(x\right)+\log_{4}\left(x-12\right)=\log_{4}\left(4^{3}\right)$
Learn how to solve equations logarithmiques problems step by step online.
$\log_{4}\left(x\right)+\log_{4}\left(x-12\right)=\log_{4}\left(4^{3}\right)$
Learn how to solve equations logarithmiques problems step by step online. log4(x)+log4(x+-12)=3. Express the numbers in the equation as logarithms of base 4. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=4 and y=x-12. Apply the formula: \log_{b}\left(b^a\right)=a, where a=3 and b=4. Apply the formula: x\left(a+b\right)=xa+xb, where a=x, b=-12 and a+b=x-12.
Final answer to the problem
$x=16$
