Final answer to the problem
$x=4$
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Express the numbers in the equation as logarithms of base $2$
$\log_{2}\left(x\right)+\log_{2}\left(x-3\right)=\log_{2}\left(2^{2}\right)$
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$\log_{2}\left(x\right)+\log_{2}\left(x-3\right)=\log_{2}\left(2^{2}\right)$
Learn how to solve problems step by step online. log2(x)+log2(x+-3)=2. Express the numbers in the equation as logarithms of base 2. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=2 and y=x-3. Apply the formula: \log_{b}\left(b^a\right)=a, where a=2 and b=2. Apply the formula: x\left(a+b\right)=xa+xb, where a=x, b=-3 and a+b=x-3.
Final answer to the problem
$x=4$
