Final answer to the problem
$x=5$
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Express the numbers in the equation as logarithms of base $10$
$\log \left(x\right)+\log \left(x-3\right)=\log \left(10^{1}\right)$
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$\log \left(x\right)+\log \left(x-3\right)=\log \left(10^{1}\right)$
Learn how to solve problems step by step online. log(x)+log(x+-3)=1. Express the numbers in the equation as logarithms of base 10. Apply the formula: x^1=x, where x=10. Apply the formula: \log_{a}\left(x\right)+\log_{a}\left(y\right)=\log_{a}\left(xy\right), where a=10 and y=x-3. Apply the formula: \log_{a}\left(x\right)=\log_{a}\left(y\right)\to x=y, where a=10, x=x\left(x-3\right) and y=10.
Final answer to the problem
$x=5$
