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Apply the formula: $x\cdot x^n$$=x^{\left(n+1\right)}$, where $x^nx=\left(x+y\right)\left(x+y\right)^2$, $x=x+y$, $x^n=\left(x+y\right)^2$ and $n=2$
Apply the formula: $a+b$$=a+b$, where $a=2$, $b=1$ and $a+b=2+1$