Exercice
$\left(6x^2+19x-5\right):\left(2x-3\right)$
Solution étape par étape
1
Diviser $6x^2+19x-5$ par $2x-3$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}-3;}{\phantom{;}3x\phantom{;}+14\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}-3\overline{\smash{)}\phantom{;}6x^{2}+19x\phantom{;}-5\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}-3;}\underline{-6x^{2}+9x\phantom{;}\phantom{-;x^n}}\\\phantom{-6x^{2}+9x\phantom{;};}\phantom{;}28x\phantom{;}-5\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-3-;x^n;}\underline{-28x\phantom{;}+42\phantom{;}\phantom{;}}\\\phantom{;-28x\phantom{;}+42\phantom{;}\phantom{;}-;x^n;}\phantom{;}37\phantom{;}\phantom{;}\\\end{array}$
$3x+14+\frac{37}{2x-3}$
Réponse finale au problème
$3x+14+\frac{37}{2x-3}$