Final answer to the problem
$y=\frac{-zxa}{az+ax+zx}$
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Step-by-step Solution
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- Find dy/dx
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1
Multiply the single term $\left(a+y\right)\left(1+a^{-1}z\right)$ by each term of the polynomial $\left(1+a^{-1}x\right)$
$\left(a+y\right)\left(1+a^{-1}z\right)+a^{-1}x\left(a+y\right)\left(1+a^{-1}z\right)=a+x+y+z$
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$\left(a+y\right)\left(1+a^{-1}z\right)+a^{-1}x\left(a+y\right)\left(1+a^{-1}z\right)=a+x+y+z$
Learn how to solve problems step by step online. Solve the equation with radicals (1+a^(-1)x)(a+y)(1+a^(-1)z)=a+xyz. Multiply the single term \left(a+y\right)\left(1+a^{-1}z\right) by each term of the polynomial \left(1+a^{-1}x\right). Multiply the single term 1+a^{-1}z by each term of the polynomial \left(a+y\right). Multiply the single term a by each term of the polynomial \left(1+a^{-1}z\right). Apply the formula: x^0=1.
Final answer to the problem
$y=\frac{-zxa}{az+ax+zx}$
