$\int_{0}^{1}\frac{1}{\left(x+1\right)\left(x^2+1\right)}dx$

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Final answer to the problem

$\frac{1}{2}\ln\left|2\right|+\frac{\pi }{8}-\frac{1}{4}\ln\left|2\right|$
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Step-by-step Solution

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Rewrite the fraction $\frac{1}{\left(x+1\right)\left(x^2+1\right)}$ in $2$ simpler fractions using partial fraction decomposition

$\frac{1}{2\left(x+1\right)}+\frac{-\frac{1}{2}x+\frac{1}{2}}{x^2+1}$

Learn how to solve calcul intégral problems step by step online.

$\frac{1}{2\left(x+1\right)}+\frac{-\frac{1}{2}x+\frac{1}{2}}{x^2+1}$

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Learn how to solve calcul intégral problems step by step online. int(1/((x+1)(x^2+1)))dx&0&1. Rewrite the fraction \frac{1}{\left(x+1\right)\left(x^2+1\right)} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int_{0}^{1}\left(\frac{1}{2\left(x+1\right)}+\frac{-\frac{1}{2}x+\frac{1}{2}}{x^2+1}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{1}\frac{1}{2\left(x+1\right)}dx results in: \frac{1}{2}\ln\left(2\right). The integral \int_{0}^{1}\frac{-\frac{1}{2}x+\frac{1}{2}}{x^2+1}dx results in: -\frac{1}{4}\ln\left(2\right)+\frac{\pi }{8}.

Final answer to the problem

$\frac{1}{2}\ln\left|2\right|+\frac{\pi }{8}-\frac{1}{4}\ln\left|2\right|$

Exact Numeric Answer

$0.565986$

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Plotting: $\frac{1}{\left(x+1\right)\left(x^2+1\right)}$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Calcul intégral

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