Final answer to the problem
$\frac{\arctan\left(\frac{x}{\sqrt{13-6x}}\right)}{\sqrt{13-6x}}+C_0$
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Apply the formula: $\int\frac{n}{x^2+b}dx$$=\frac{n}{\sqrt{b}}\arctan\left(\frac{x}{\sqrt{b}}\right)+C$, where $b=13-6x$ and $n=1$
$\frac{1}{\sqrt{13-6x}}\arctan\left(\frac{x}{\sqrt{13-6x}}\right)$
Learn how to solve intégrales de fonctions rationnelles problems step by step online.
$\frac{1}{\sqrt{13-6x}}\arctan\left(\frac{x}{\sqrt{13-6x}}\right)$
Learn how to solve intégrales de fonctions rationnelles problems step by step online. int(1/(x^2-6x+13))dx. Apply the formula: \int\frac{n}{x^2+b}dx=\frac{n}{\sqrt{b}}\arctan\left(\frac{x}{\sqrt{b}}\right)+C, where b=13-6x and n=1. Apply the formula: a\frac{b}{x}=\frac{ab}{x}. As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration C.
Final answer to the problem
$\frac{\arctan\left(\frac{x}{\sqrt{13-6x}}\right)}{\sqrt{13-6x}}+C_0$
