$\frac{dy}{dx}=\left(x+y\right)^2$

Step-by-step Solution

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Final answer to the problem

$y=\tan\left(x+C_0\right)-x$
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Step-by-step Solution

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When we identify that a differential equation has an expression of the form $Ax+By+C$, we can apply a linear substitution in order to simplify it to a separable equation. We can identify that $\left(x+y\right)$ has the form $Ax+By+C$. Let's define a new variable $u$ and set it equal to the expression

$u=x+y$

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$u=x+y$

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Learn how to solve equations différentielles problems step by step online. dy/dx=(x+y)^2. When we identify that a differential equation has an expression of the form Ax+By+C, we can apply a linear substitution in order to simplify it to a separable equation. We can identify that \left(x+y\right) has the form Ax+By+C. Let's define a new variable u and set it equal to the expression. Isolate the dependent variable y. Differentiate both sides of the equation with respect to the independent variable x. Now, substitute \left(x+y\right) and \frac{dy}{dx} on the original differential equation. We will see that it results in a separable equation that we can easily solve.

Final answer to the problem

$y=\tan\left(x+C_0\right)-x$

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Function Plot

Plotting: $\frac{dy}{dx}-\left(x+y\right)^2$

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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