Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choisir une option
- Equation différentielle exacte
- Équation différentielle linéaire
- Équation différentielle séparable
- Equation différentielle homogène
- Produit de binômes avec terme commun
- Méthode FOIL
- Load more...
We can identify that the differential equation $\frac{dy}{dx}=\frac{x+3y}{x-y}$ is homogeneous, since it is written in the standard form $\frac{dy}{dx}=\frac{M(x,y)}{N(x,y)}$, where $M(x,y)$ and $N(x,y)$ are the partial derivatives of a two-variable function $f(x,y)$ and both are homogeneous functions of the same degree
Learn how to solve problems step by step online.
$\frac{dy}{dx}=\frac{x+3y}{x-y}$
Learn how to solve problems step by step online. dy/dx=(x+3y)/(x-y). We can identify that the differential equation \frac{dy}{dx}=\frac{x+3y}{x-y} is homogeneous, since it is written in the standard form \frac{dy}{dx}=\frac{M(x,y)}{N(x,y)}, where M(x,y) and N(x,y) are the partial derivatives of a two-variable function f(x,y) and both are homogeneous functions of the same degree. Use the substitution: y=ux. Expand and simplify. Apply the formula: b\cdot dy=a\cdot dx\to \int bdy=\int adx, where a=\frac{1}{x}, b=\frac{1-u}{\left(u+1\right)^{2}}, dy=du, dyb=dxa=\frac{1-u}{\left(u+1\right)^{2}}du=\frac{1}{x}dx, dyb=\frac{1-u}{\left(u+1\right)^{2}}du and dxa=\frac{1}{x}dx.