Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choisir une option
- Produit de binômes avec terme commun
- Méthode FOIL
- Load more...
Apply the formula: $\frac{d}{dx}\left(a^b\right)$$=y=a^b$, where $d/dx=\frac{d}{dx}$, $a=x$, $b=\sqrt{x}$, $a^b=x^{\left(\sqrt{x}\right)}$ and $d/dx?a^b=\frac{d}{dx}\left(x^{\left(\sqrt{x}\right)}\right)$
Learn how to solve différenciation logarithmique problems step by step online.
$y=x^{\left(\sqrt{x}\right)}$
Learn how to solve différenciation logarithmique problems step by step online. d/dx(x^x^(1/2)). Apply the formula: \frac{d}{dx}\left(a^b\right)=y=a^b, where d/dx=\frac{d}{dx}, a=x, b=\sqrt{x}, a^b=x^{\left(\sqrt{x}\right)} and d/dx?a^b=\frac{d}{dx}\left(x^{\left(\sqrt{x}\right)}\right). Apply the formula: y=a^b\to \ln\left(y\right)=\ln\left(a^b\right), where a=x and b=\sqrt{x}. Apply the formula: \ln\left(x^a\right)=a\ln\left(x\right), where a=\sqrt{x}. Apply the formula: \ln\left(y\right)=x\to \frac{d}{dx}\left(\ln\left(y\right)\right)=\frac{d}{dx}\left(x\right), where x=\sqrt{x}\ln\left(x\right).
