Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choisir une option
- Produit de binômes avec terme commun
- Méthode FOIL
- Load more...
Apply the formula: $\frac{d}{dx}\left(a^b\right)$$=y=a^b$, where $d/dx=\frac{d}{dx}$, $a=1+\frac{1}{x}$, $b=x$, $a^b=\left(1+\frac{1}{x}\right)^x$ and $d/dx?a^b=\frac{d}{dx}\left(\left(1+\frac{1}{x}\right)^x\right)$
Learn how to solve simplifier des expressions trigonométriques problems step by step online.
$y=\left(1+\frac{1}{x}\right)^x$
Learn how to solve simplifier des expressions trigonométriques problems step by step online. d/dx((1+1/x)^x). Apply the formula: \frac{d}{dx}\left(a^b\right)=y=a^b, where d/dx=\frac{d}{dx}, a=1+\frac{1}{x}, b=x, a^b=\left(1+\frac{1}{x}\right)^x and d/dx?a^b=\frac{d}{dx}\left(\left(1+\frac{1}{x}\right)^x\right). Apply the formula: y=a^b\to \ln\left(y\right)=\ln\left(a^b\right), where a=1+\frac{1}{x} and b=x. Apply the formula: \ln\left(x^a\right)=a\ln\left(x\right), where a=x and x=1+\frac{1}{x}. Apply the formula: \ln\left(y\right)=x\to \frac{d}{dx}\left(\ln\left(y\right)\right)=\frac{d}{dx}\left(x\right), where x=x\ln\left(1+\frac{1}{x}\right).